X^2+3.5x-24=0

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Solution for X^2+3.5x-24=0 equation:



X^2+3.5X-24=0
a = 1; b = 3.5; c = -24;
Δ = b2-4ac
Δ = 3.52-4·1·(-24)
Δ = 108.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.5)-\sqrt{108.25}}{2*1}=\frac{-3.5-\sqrt{108.25}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.5)+\sqrt{108.25}}{2*1}=\frac{-3.5+\sqrt{108.25}}{2} $

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